(8g^3+19g^2-12g+9)/(g+3)

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Solution for (8g^3+19g^2-12g+9)/(g+3) equation:


D( g )

g+3 = 0

g+3 = 0

g+3 = 0

g+3 = 0 // - 3

g = -3

g in (-oo:-3) U (-3:+oo)

(8*g^3+19*g^2-(12*g)+9)/(g+3) = 0

(8*g^3+19*g^2-12*g+9)/(g+3) = 0

8*g^3+19*g^2-12*g+9 = 0

8*g^3+19*g^2-12*g+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

g = 1

8*g^3+19*g^2-12*g+9 = 24

1

-1

g = -1

8*g^3+19*g^2-12*g+9 = 32

-1

3

g = 3

8*g^3+19*g^2-12*g+9 = 360

3

-3

g = -3

8*g^3+19*g^2-12*g+9 = 0

-3

g+3

8*g^2-5*g+3

8*g^3+19*g^2-12*g+9

g+3

-8*g^3-24*g^2

9-5*g^2-12*g

5*g^2+15*g

3*g+9

-3*g-9

0

8*g^2-5*g+3 = 0

DELTA = (-5)^2-(3*4*8)

DELTA = -71

DELTA < 0

g in { -3}

g+3 = 0

1 = 0

g belongs to the empty set

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